Question

An object of volume 100 cm3 is weights 2 kgf in air. It is completely immersed in a liquid of density 1.8 x 10 power 3 kgm-3.
Find the following:
a) upthrust due to liquid
b) weight of the body in the liquid
c) apparent weight of the body

Answer 1

Answer:

Weight of body in liquid = Actual weight - upthrust

Upthrust exerted =Vρg

Where, V= volume

ρ= density

g=acc. due to gravity

Upthrust=100×10

−9

m

3

×1.8×10

3

kgm

−3

×10

⇒0.18kgf

So, Weight of body in liquid = Actual weight - upthrust

⇒5−0.18=4.82kgf