Question

An object os placed 10 cm from a cocave mirror. the focal length is 5 cm. determine the position, nature and magnification of the image
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Answer 1

The image distance :

1/d¡ = 1/f – 1/d₀ 

= 1/5 – 1/10

= 2/10 – 1/10

= 1/10

d¡= 10/1 = 10 cm

The distance of the imaɡe is 10 cm.

The magnification :

m = -d¡/ d₀ = -10/10 = -1

Here, 1 means that the image is the same as the object is. The minus sign shows that the image is in inverted nature. 

Answer 2

Answer:

Given:

u=(-10) cm

f=(-5) cm

Concave mirror

To find:

magnification and nature of image and position

Solution:

Using mirror formula

$\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$

$\frac{ - 1}{5} + \frac{1}{10} = \frac{1}{v}$

$\frac{1}{v} = \frac{ - 1}{10}$

v=(-10) cm

Magnification=-v/u

=10/-10

=-1

Nature:Image is real, inverted and of same size as of object. Object is placed at C(2f)