An object performing S.H.M. with mass of 0.5 kg, force constant 10N/m and amplitude 3cm, What is the total energy of object?
(Ans : E = 0.0045J )
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we know, total energy of object is given by
where is the force constant and A is the amplitude of object.
given,
so, T.E = 1/2 × 10 × (3 × 10^-2)²
= 1/2 × 10 × 9 × 10^-4
= 0.0045 J
where is the force constant and A is the amplitude of object.
given,
so, T.E = 1/2 × 10 × (3 × 10^-2)²
= 1/2 × 10 × 9 × 10^-4
= 0.0045 J
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