Question

an object placed 4 cm in front of a concave mirror of focal lenght 12 cm find the nature and size of the image formed​

Answer 1

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Explanation:

object distance u= -4cm

focal length  f= 12cm

image distance v= ?

According to the mirror formula

 1/v+1/u=1/f

 1/v + 1/-4 = 1/-12

 1/v= -1/12+1/4= (-1+3)12=2/12

so we get 1/v=1/6 so v will be 6 as it gets reciprocaled.....

The image is formed 6 cm behind the mirror and is virtual and erect

Answer 2

u = - 4 cm, f = -12 cm

1/v + 1/u = 1/f

1/v + 1/-4 = 1/-12

1/v = -1/12 + 1/4 = (-1 + 3)12 = 2/12

V = 6 cm

The image is formed at a distance of 6 cm behind the mirror.

The image is virtual and erect.

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