An object placed 50cm from a lens produces a virtual image at a distance of 10cm in front of a lens. What is the focal length of lens?
Answers
Answered by
11
hey dear here is ur solution___
u=-50
v=-10
1/v-1/u=1/f
1/-10-1/-50=1/f
-5+1/50=1/f
50/-4=f
-12.5=f
u=-50
v=-10
1/v-1/u=1/f
1/-10-1/-50=1/f
-5+1/50=1/f
50/-4=f
-12.5=f
Answered by
1
here is the solution of your question.
u=-50cm
v=+10cm
f=?
therefore, 1/f=1/v-1/u
=, 1/f=1/10+1/50
= 1/f=5+1/50
=1/f=6/50
=f=50/6
=f=25/3
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