Question

an object placed 60 cm in front of concave mirror. the real image formed by the mirror is located 30 cm in front of the mirror . what is the object magnification ​

Answer 1

Answer: -0.5

Explanation:u=-60 ,v=-30

M=-v/u =-(-30)/-60 =30/-60

=-0.5

Answer 2

Answer:

The object's magnification is -0.5.

Explanation:

The magnification of a mirror is given as,

$m=\frac{-v}{u}$         (1)

Where,

m=magnification of the mirror

v=image distance from the mirror

u=object distance from the mirror

From the question we have,

v=-30cm           (∴ negative sign because the image formed is real)

u=-60cm

By substituting the value of v and u in the equation (1) we get;

$m=\frac{-(-30)}{-60}=\frac{-30}{60}=\frac{-1}{2}=-0.5$

Hence, the object magnification is -0.5.