An object placed at a distance of 10 cm from a convex mirror of focal length 15 cm, find the position and nature of the image.
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Position=6cm from pole (opposite side of the image)
Nature :_ Virtual&Erect
Nature :_ Virtual&Erect
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Answer:
+ 6 cm
Explanation:
Given :
Object distance = - 10 cm
Focal length = + 15 cm
We have to find image distance.
We know :
1 / f = 1 / v + 1 / u
1 / v = 1 / f - 1 / u
1 / v = 1 / 15 + 1 / 10
1 / v = 1 / 6
v = + 6 cm
Hence .image distance is 6 cm from the mirror behind it.
The image is erect and virtual.
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