Question

an object placed at a distance of 15cm forms a virtual image of one third the size of object find the nature and focal length​

Answer 1

M = v/u = 3 therefore v = 3u

use The Formula

1/u + 1/3u = 1/15

4/3u = 1/15

3u/4 = 15

Giving u=20 & v=60

Answer 2

Answer:

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