An object released from a height undergoes uniform acceleration of 10m/s
2 and attains
final velocity of 28m/s before touching the ground. What was its average velocity?
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1
a=10m/s²
u=0
v=28m/s
Since object undergoes uniform acceleration,
So laws of motion can be applied.
Since v=u+at
=>28=0+10t
=>28=10t
=>t=2.8seconds.
So average velocity =u+v/2
=>Average velocity=0+28/2
=>Average velocity=14m/s
Hope it is helpful.
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