an object requires a speed of 50meter per second in 10s calculate acseration
Answers
Answer:
M = 5 kg
u = 10m/s
K E = 1/2×m×u^2
= 1/2×5×100
= 250J
loss in KE = gain in PE
→ PE = 250
also PE = m×g×h
250=5×10×h
→ H = 5m
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skyfall63 Ambitious
Maximum height attained by the body is 5 m.
Given:
Mass of the body, M = 5 kg
Speed with which the body travels, u = 10 m/s
Solution:
We have to initially find the Kinetic difference,
The formula for Kinetic difference is,
The, Potential energy of the body is 250 J, when it reaches the highest point.
Loss in K.E = gain in P.E
→ P.E = 250 J
And the formula for potential difference is,
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