Question

An object rotates in circular path of radius 5 m. calculate it's distance and displacement after completing 2 and half round

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Distance\:travel=78.5\:m}}}$

$\green{\tt{\therefore{Displacement=10\:m}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given:}} \\ \tt: \implies Radius = 5 \: m \\ \\ \tt: \implies Revolution = 2 \: and \: half \: round \\ \\ \red{\underline \bold{To \: Find:}} \\ \tt: \implies Distance \: travel = ? \\ \\ \tt: \implies Displacement= ?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies Circumference \: of \: path = 2\pi r \\ \\ \tt: \implies Circumference \: of \: path =2 \times 3.14\times 5 \\ \\ \green{\tt: \implies Circumference \: of \: path =31.4 \: m} \\ \\ \bold{For \: Distance : }\\ \tt: \implies Distance \: travel = 31.4 \times 2.5 \\ \\ \green{\tt: \implies Distance \: travel =78.5 \: m} \\ \\ \bold{For \: Displacement : } \\ \tt: \implies Displacement = 2 \: radius \\ \\ \tt: \implies Displacement = 2 \times 5 \\ \\ \green{\tt: \implies Displacement = 10 \: m}$

Answer 2

AnswEr :

• Distance = 25π m
• Displacement = 10 m

From the Question,

• The radius of the circle (r) = 5 m

• The particle completes 2½ rounds on the circular path

To finD : Distance and Displacement

Now,

Distance covered by the object would be : 2 of Circumference + ½ of Circumference

Thus,D = 2(2πr) + ½(2πr)

→ D = 5πr

→ D = 5(5)π

→ D = 25π m

Also,

Displacement of the object : Diameter

Thus,

S = 2r

→ S = 2(5)

→ S = 10 m