Question

an object's momentum changes from 14 Ns to 22 Ns in 4 sec. the amount of force acted is

4N

2N

4.5N

2.5N
​

Answer 1

• Initial moment=P_1=14Ns
• Final momentum=P_2=22Ns
• Time=t=4s

$\boxed{\sf F_{net}=\dfrac{\Delta P}{t}}$

$\\ \Large\sf\longmapsto F_{net}=\dfrac{P_2-P_1}{t}$

$\\ \Large\sf\longmapsto F_{net}=\dfrac{22-14}{4}$

$\\ \Large\sf\longmapsto F_{net}=\dfrac{8}{4}$

$\\ \Large\sf\longmapsto F_{net}=2N$

• Option b is correct.

Answer 2

$Initial \: \:moment=P_1=14Ns \\ Final \: \: momentum=P_2=22Ns \\ Time=t=4s$

$\boxed{\sf F_{net}=\dfrac{\Delta P}{t}}$

$\begin{gathered}\\ \Large\sf\longmapsto F_{net}=\dfrac{P_2-P_1}{t}\end{gathered}$

$\begin{gathered}\\ \Large\sf\longmapsto F_{net}=\dfrac{22-14}{4}\end{gathered}$

$\begin{gathered}\\ \Large\sf\longmapsto F_{net}=\dfrac{8}{4}\end{gathered}$

$\begin{gathered}\\ \Large\sf\longmapsto F_{net}=2N\end{gathered}$

option b is correct .