Question

an object start from rest attinied a veloctiy of 42 km/h in 5 seconds at uniform rate the acceleration of object is​

Answer 1

Step-by-step explanation:

We have to find out acceleration: We will denote acceleration by a and distance travelled by s. Hence the acceleration is 864km/h2.

Answer 2

Answer:

v=u+at 

a=(v-u)/t                   -----------(1)

v=72 km/h

 =20m/s

u=0

t=5*60 sec =300sec

by putting values of v,u,t in (1)

a=1/15 m/s2

s=ut +(1/2)at2

 =0+(1/2)(1/15)(300)(300)

=3km