Question

An object start from rest travels 8ms-2 acceleration in 10 sec find speed and distance

Answer 1

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Since the body is in rest, u=0

time t = 10 sec

a = 8

v = u+at

v = 0 + 8 x 10 = 80 m/s

Distance = S = ut + 1/2 at²

a = 8

u = 0

t = 10

so, your answer is

1/2 x 10 x 10 x 8 = 200 m

Answer 2

here,

initial velocity (u) = 0

time (t) = 10sec

acceleration (a) = 8m/s²

we have,

v = u+ at

v = 0+(8×10)

v = 80m/s

S = ut+(1/2)at²

S = 0+(1/2)×8×10×10

S = 4×10×10

S = 400m

therefore velocity = 80m/s

ans distance = 400m