Question

An object start from rest with acceleration 2 M/S2 . What displacement it cover in 1 sec​

Answer 1

Provided that:

• Initial velocity = 0 mps
• Acceleration = 2 mps sq.
• Time = 1 second

To calculate:

• The displacement

Solution:

• The displacement = 1 m

Using concept:

• Second equation of motion

Using formula:

• s = ut + ½ at²

Where, a denotes acceleration, u denotes initial velocity, s denotes displacement or distance or height, t denotes time taken.

Required solution:

»»» s = ut + ½ at²

»»» s = 0(1) + ½ × 2 × (1)²

»»» s = 0 + ½ × 2 × 1 × 1

»»» s = 0 + ½ × 2

»»» s = ½ × 2

»»» s = 1/1 × 1

»»» s = 1 m

»»» Displacement = 1 m

Know more:

$\begin{gathered}\boxed{\begin{array}{c}\\ {\pmb{\sf{Three \: equation \: of \: motion}}} \\ \\ \sf \star \: v \: = u \: + at \\ \\ \sf \star \: s \: = ut + \: \dfrac{1}{2} \: at^2 \\ \\ \sf \star \: v^2 - u^2 \: = 2as\end{array}}\end{gathered}$