Question

An object start moving from rest on a straight line path with uniform acceleration and covers a distance of 100 m in first 10 s. The distance it covers in next 5 s is___

Answer 1

a = 2S / t²
= (2 × 100 m) / (10 s)²
= 2 m/s²

After 10 s Velocity is
v = u + at
= 0 + (2 m/s² × 10 s)
= 20 m/s

After 15 s Velocity is
v’ = u + at’
= 0 + (2 m/s² × 15 s)
= 30 m/s

S’ = (v’² - u’²) / (2a)
= (30² - 20²) / (2 × 2 m/s²)
= 125 m

Distance covered in next 5 seconds is 125 m