Question

an object starting from rest accelerated uniformly for 2 sec attain a velocity 12.5 m/s. find distance travelled by an object​

Answer 1

Answer:

12.5m

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Answer 2

Answer:

U = 0( becuz its starting from rest )

t = 2s

V = 12.5 m/s

first find the acceleration

a = v-u/t

a = 12.5-0/2

a = 6.25 m/s²

apply

s = ut + 1/2at²

s = 0×2 + 1/2(6.25×2×2)

s = 0 + 1/2 ×25

s = 25/2

s = 12.5 meters

Explanation:

hope it helps