Question

an object starting from rest at t=0 undergoes constant acceleration 2m/s^2. what is the distance travelled by the object when t=5? what is the velocity of the at t=5?
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Answer 1

Answer:

Explanation:apply s=ut+1/2at×t

U=0; a=2; t=5

For finding velocity apply

V=u+at

Answer 2

It's simple

Use the formula s=ut+1/2at^2, s is for distance and t for time and a for acceleration

fir velocity use v^2-u^2 =2as

or v=u+at

So the answer for t=5 is 25m and velocity is 10 m/s