Question

An object starting from rest attains a speed of 25m/s after travelling a distance of 50 m. calculate the accelaration produced and the total time taken to cover that distance.

Answer 1

the time taken is v/s=25/50
                                =0.5s
the accelaration      = v-u/t
                                 =25/0.5
                                =50m/s²

Answer 2

Answer:

Acceleration of the object= 6.25 m/S^2 and time=04 seconds

Explanation:

Given

Final Velocity of the object= 25 m/s

Distance travelled by the object= 50m

We know that

v^2= u^2+2*a*s

where v= Final velocity of the object

u= Initial velocity of the object

a= Acceleration of the object

s= Distance travelled by the object

So,

(25)^2= 0+ 2* a* 50

625= 100a

6.25= a

Hence Acceleration of the object= 6.25 m/s^2

We know that

v= u+ a*t

25= (6.25)*t

t= 04 seconds

Hence Time taken by the object= 04 seconds

So,

Acceleration of the object= 6.25 m/s^2 & Time Taken by the object= 04 seconds

#SPJ3