an object starting from rest attains a velocity of 20m/s in 5 sec calculate the distance travelled during this time interval
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Answered by
25
s= ut +1/2at^2
u=0
v=20
t = 5
so a = v-u/t
20-0/5=4m/s^2
s= 0+1/2× 4× 5^2
=50m......
MARK AS BRAINLIEST IF YOU LIKED.....
u=0
v=20
t = 5
so a = v-u/t
20-0/5=4m/s^2
s= 0+1/2× 4× 5^2
=50m......
MARK AS BRAINLIEST IF YOU LIKED.....
Answered by
4
u=0
v=20
t = 5
so a = v-u/t
20-0/5=4m/s^2
s= 0+1/2× 4× 5^2
50
mark it as the brainliest
v=20
t = 5
so a = v-u/t
20-0/5=4m/s^2
s= 0+1/2× 4× 5^2
50
mark it as the brainliest
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