Question

An object starting from rest covers 20m in first two sec and 160 metres in next 4 seconds . What is its velocity after 7 second for start.
In what type of relationship please tell​

Answer 1

Answer:

From s=ut+ 1/2at ²

In first 2 s,

s=20m

20= 1/2a(2)

=2a

a=10 m/s

Velocity at the end of 2 s is

v=u+at=0+10×2=20m/s

In next 4s, s=ut+ 1/2a,t²

160=20×4+1/2 a(4)²

80=8a

a=10m/s

It shows that acceleration is uniform. From v=u+at

v=0+10×7=70 m/s

Answer 2

Answer:

Uniform circular motion can be described as the motion of an object in a circle at a constant speed. As an object moves in a circle, it is constantly changing