Question

an object starting from rest covers a distance of hundred metres in 5 seconds find the acceleration an and the final velocity

Answer 1

Answer:

Acceleration of the object = 8 m/s²

the final velocity of the object = 40 m/s

Step by step explanations :

given that,

an object starting from rest covers a distance of hundred metres in 5 seconds

here,. initial velocity of the object =

0 m/s

[ball was at rest]

given distance travelled by it = 100 m

let the final velocity of the object be v

now,

we have,

initial velocity(u) = 0 m/s

final velocity(v) = v

distance travelled(s) = 100 meter

time taken(t) = 5 seconds

by the equation of motion,

S = ut + ½ at²

putting the values,

100 = 0(5) + ½ a (5)(5)

100 = 25a/2

25a = 200

a = 200/25

a = 8 m/s²

so,

Acceleration of the object = 8 m/s²

also,

v² = u² + 2as

again putting the values,

v² = (0)² + 2(8)(100)

v² = 1600

v = 40 m/s

so,

the final velocity of the object

= 40 m/s

_________________

Answers:

Acceleration of the object = 8 m/s²

final velocity of the object = 40 m/s

Answer 2

Answer :-

a = 8m/s²

v = 40 m/s

Given :-

u = 0 m/s

t = 5s

S = 100m

To find :-

The acceleration of the object and it's final velocity.

Solution:-

As per given question,

By using 2nd equation of motion:-

$\huge \boxed{S = ut + \dfrac{1}{2}at^2}$

Put the given values,

→$100 = 0 \times 5 +\dfrac{1}{2} a \times (5)^2$

→$100 = \dfrac{1}{2} 25a$

→$200= 25a$

→$a = \dfrac{200}{25}$

→$a = 8 m/s^2$

We have ,

a = 4m/s²

By using first equation of motion:-

$\huge \boxed{v = u+at}$

→$v = 0 + 8\times 5$

→$v = 40 m/s$

hence,

The acceleration of the object will be 8 m/s² and final velocity will be 40 m/s.