Question

an object starting from rest covers distance of 20 metre in 2 second and 60 m in next 4 second what will be the velocity after 7 seconds from the from the start​

Answer 1

Answer:

$From \:  s=ut+21at2</p><p></p><p>In \: first 2 s,</p><p></p><p>s=20m</p><p></p><p>20=21a(2)2=2a</p><p></p><p>a=10 m/s2</p><p></p><p>Velocity \: at \: the \: end \: of 2 s is </p><p></p><p>v=u+at=0+10×2=20m/s</p><p></p><p>In \: next \: 4s, s=ut+21a′t2</p><p></p><p>160=20×4+21a′(4)2</p><p></p><p>80=8a′</p><p></p><p>a′=10 m/s2</p><p></p><p>$

It shows that acceleration is uniform. From v=u+at

v=0+10×7=70 m/s

Answer: 70

Explanation:

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