Question

An object starting from rest covers20 meters in first 2 second and 160meter in 4second what is its velocity after 7 second from the start

Answer 1

Answer:

Explanation:

As we know s=ut+1/2at^2

So,

t=2 and s=20

20=1/2×4×a. {u=0}

Acceleration,

a=10m/sec^2

Now ,

Velocity after 7 sec

V=u+at

V=at

V=7×10=70m/sec