Question

an object starting from rest moves with an acceleration of 2 m/s ^ 2.find out the distance travelled by the object in 4s​

Answer 1

${\red{\underline{\underline{\bold{Given:-}}}}}$

• Initial velocity ,u = 0m/s (rest)
• Acceleration ,a = 2m/s²
• Time taken ,t = 4s

${\blue{\underline{\underline{\bold{To Find:-}}}}}$

• Distance travelled ,s

${\green{\underline{\underline{\bold{Solution:-}}}}}$

According to the Question

It is given that the object start from rest & accelerate at 2m/s² for 4 s. we have to calculate the distance covered by object in this case. Using 2nd equation of motion

• s = ut + 1/2at²

where

• v is the final velocity
• a is the acceleration
• u is the initial velocity
• t is the time taken
• s is the distance covered

Substitute the value we get

$:\implies$ s = 0×4 + 1/2× 2 × 4²

$:\implies$ s = 0 + 1/2× 2 × 16

$:\implies$ s = 16 m

• $\large\pink{{\underline{\boxed{\textbf{Hence,\:the\:distance\: covered\: by\: the\: object\: is\: 16metres}}}}}$

Answer 2

Given :-

An object starting from rest moves with an acceleration of 2 m/s²

To Find :-

Distance travelled after 4 sec

Solution :-

We know that

s = ut + 1/2 × at²

s = (0)(4) + 1/2 × 2 × (4)²

s = 0 + 1/2 × 2 × 16

s = 0 + 16

s = 16

Hence

Distance travelled by the object after 4 second is 16 m

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