Question

An object starting from rest travel 40 m in first 2s and 200 m in next 4s what will be the velocity after5s from the start

Answer 1

Given object starts from rest, i.e., u = 0, t = 2 s and s = 40 m

According to equation of motion, $s=ut+\cfrac{1}{2}at^2$

Substituting the values,

$40=(0)(2)+\cfrac{1}{2}(a)(2)^2$

$a=20 \text{ m/s}^2$

Now, we know that,

$v=u+at$

so, after 5 s from the start, the velocity of an object will be

$v=0+(20)(5)=100 \text { m/s}$