Physics, asked by simransandhugmail, 1 year ago

An object starting from rest travels 20m in first 2s and 160m in next 4s what will be the velocity after 7s from start?

Answers

Answered by chiefLucky
64
Velocity in first two seconds=20/2=10 m/s=u
Velocity in next 4 seconds=160/4=40 m/s=v
Total time=6 seconds
Acceleration=(v-u)/t
=40-10/6=30/6=5 m/s2
Now take initial velocity as 40 m/s from 6 seconds.
Therefore velocity after 7 seconds=u+at
=40+5×1
=40+5=45 m/s
Plz mark as brainliest if you found me helpful :D

simransandhugmail: thnk u sooooo much
chiefLucky: No prob
Answered by anup15416668nnRitik
13

Explanation:

Given:

Initial velocity = u =0m/s

Distance travelled =S=20m

time =t=2sec.

From second equation of motion:

S=ut + 1/2 at²

20= 0*2+ 1/2a2²

20=2a

a=10m/s²

velocity at the end of 2sec:

V=u+at

=0+10*2

V=20m/s

After 4sec, it covers a distance of 160m

so,

160=20*4+1/2(a¹)4²

160=80+2a

8a¹=80

a¹=10m/s²

It shows acceleration is uniform.

So, velocity at end of 7 sec from start:

V=u+at

= 0 + 10*7

=70m/s

∴the velocity after 7 sec from the start is 70m/s

Read

Similar questions