Question

An object starting from rest travels with a uniform acceleration of 8m/s². Calculate the velocity and distance traveled after 1 minute. ​

Answer 1

v=u+at

u=0

=0+5m/s

2

×60s

a=5m/s

2

=0+300m/s

t=1 min

So, t=60sec

=300m/s

s=ut+1/2at

2

=0×60+1/2×5×60

2

=9000m

Answer 2

${\underline{\underline{\frak\red{✪ \: Question:-}}}}$

An object starting from rest travels with a uniform acceleration of 8m/s². Calculate the velocity and distance traveled after 1 minute.

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${\underline{\underline{\frak\red{✪ \: Answer:-}}}}$

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${\underline{\boxed{\sf\purple{GIVEN}}}}$

object is start from rest = u = 0

acceleration = 8m/s²

time = 1 minute

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${\underline{\boxed{\sf\purple{TO \: FIND \: IT'S \: VELOCITY.}}}}$

⠀➼initial speed = 0

⠀➼final velocity = v

⠀➼acceleration = 8m/s²

⠀➼time = 1 minute

t = 1 min

So, t = 60sec

⠀⠀⠀= 300m/s

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From newton first equation of kinematics,

⠀⠀⠀⠀⠀${\boxed{\frak\pink{:. \: s=ut+ \frac{1}{2at} }}}$

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⠀⠀⠀⠀$\sf{:⟹ \: 0 \times 60 + \frac{1}{2} \times 8 \times {60}^{2} }$

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⠀⠀⠀⠀$\sf{:⟹ 0 + \frac{1}{\cancel2} \times \cancel8 \times 60 \times 60}$

⠀⠀⠀⠀

⠀⠀⠀⠀$\sf{:⟹ \: 4 \times 60 \times 60}$

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⠀⠀⠀⠀⠀⠀${\boxed{\sf\red{ 1440 m}}}$

⠀⠀⠀⠀

Therefore,

velocity = 1440 m .

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MORE INFORMATION.

1) = Newton first equation of kinematics

$\green{\boxed{\bf{v \: = u + at}}}★$ ⠀ ⠀

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2) = Newton second equation of

kinematics

$\green{\boxed{\bf{s \: = ut \: + \frac{1}{2}a {t}^{2}}}}★$ ⠀

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3) = Newton third equation of kinematics

${\green{ \boxed{\bf{{v}^{2} = u {}^{2} + 2as}}}}★$