Question

An object starting from rest travels with an acceleration of 5 m/s.2 Find the distance travelled by time​

Answer 1

Answer:

v=u+at

u=0

=0+5m/s

2

×60s

a=5m/s

2

=0+300m/s

t=1 min

So, t=60sec

=300m/s

s=ut+1/2at

2

=0×60+1/2×5×60

2

=9000m

Answer 2

Answer:

v=u+at

u=0

=0+5m/s²×60s

a=5m/s²

=0+300m/s

t=1 min

So, t=60sec

=300m/s

s=ut+1/2at²

=0×60+1/2×5×60²

=9000m

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