Question

An object starts from rest and accelerates uniformly in a straight line path in the positive x direction. After 12sec, it's speed is 72ms.find average velocity during first 12sec

Answer 1

Explanation:

average velocity=∆x/∆t

=x2-x1/t2-t1

=72-0/12-1

=72/12

=6m/s

Answer 2

Answer: 6m/sec

Explanation:

given

1. object starts from rest - $U=0$

2. time is$t = 12 sec$

3. to find average velocity:

according to the definition Average velocity is calculated by the formula $V = D/T ,$

where V equals the average velocity, D equals total displacement and t equals total time.

It is the average value of the known velocities. Average Velocity is defined as the total displacement travelled by the body in time t. The average velocity is denoted by Vav and can be determined using the following formula:

$average velocity = total displacement /total time$

If any distances xi and xf with their corresponding time intervals ti and tf are given we use the formula:

$Vav= Xf-Xi/ Tf-Ti$

If final Velocity V and Initial velocity U are known, we make use of the formula:

$U+V/2$

in the given question

$Vav= Xf-Xi/ Tf-Ti$

here

$X2=72\\X1=0\\T2=12\\T1= 0$

putting the values in equation we get

$72 - 0 / 12 - 0\\\\72 / 12\\\\=6m/s$

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