Question

An object starts from rest and achieves a velocity of 4 m/s in with a acceleration motion. what distance it has covered after 6 second.
[Hint - first calculate acceleratook and then use 2nd equation of motion to calculate second. ]

Answer 1

Answer:

12m

Explanation:

using 1st eq. of motion, v=u+at

4m/s = 0 + a*6s

a = 4/6 m/s²

now using 2nd eq. of motion, s = ut + 1/2at²

s = 0*6+1/2(4/6*(6)²)

s=1/2(4*6)

s= 1/2*24

s= 12m. answer