Question

An object starts from rest and attains a uniform acceleration of 25 meter be it's velocity at the end of half a meter?
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Answer 1

Given:-

• Initial velocity,u = 0 m/s

• Acceleration,a = 25 m/s²

• Distance,s = ½ m

To be calculated:-

Calculate the final velocity,v ?

Formula used:

v² = u² + 2as

Solution:-

From the third equation of motion,we have

v² = u² + 2as

★ putting the value in the above formula,we get:

v² = ( 0 )² + 2 × 25 × 1/2

v² = 0 + 50 × 1/2

v² = 50/2

v² = 25

v = √ 25

v = 5 m/s

Hence,the final velocity of object is 5 m/s.

Answer 2

✯✯ QUESTION ✯✯

An object starts from rest and attains a uniform acceleration of 25 meter be it's velocity at the end of half a meter?

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✰✰ ANSWER ✰✰

$\longmapsto\tt{Initial\:Velocity(u)=0m/s}$

$\longmapsto\tt{Distance(s)=\dfrac{1}{2}m}$

$\longmapsto\tt{Acceleration(a)=25{m/s}^{2}}$

$\longmapsto\tt{Final\:Velocity(v)=?}$

➥Using 3rd Equation : -

$\longmapsto\tt{\small{\boxed{\bold{\bold{\red{\sf{{v}{2}-{u}^{2}y=2as}}}}}}}$

➥Putting Values : -

$\longmapsto\tt{{v}^{2}-{(0)}^{2}=2\times{25}\times\dfrac{1}{2}}$

$\longmapsto\tt{{v}^{2}={\cancel{50}}\times\dfrac{1}{\cancel{2}}}$

$\longmapsto\tt{{v}^{2}=\sqrt{25}}$

$\orange\longmapsto\:\large\underline{\boxed{\bf\pink{v}\orange{=}\red{5m/s}}}$

☛ So , The final velocity is 5m/s...