Physics, asked by barenyabania, 7 months ago

an object starts from rest and attains a velocity of 54 km/hr in 5 seconds. Find
(i) acceleration.
(ii) distance travelled by the object in 10 seconds.
(iii) velocity after 8 seconds.

please answer as soon as possible ​

Answers

Answered by mohit921
1

Answer:

When t=1, the velocity of the particle is 4+2=6 m/s.

When t=2, the velocity of the particle is 4+2×2=8 m/s.

After t seconds, the velocity of the particle is 4+2t m/s.

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