an object starts from rest and attains a velocity of 54 km/hr in 5 seconds. Find
(i) acceleration.
(ii) distance travelled by the object in 10 seconds.
(iii) velocity after 8 seconds.
please answer as soon as possible
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Answer:
When t=1, the velocity of the particle is 4+2=6 m/s.
When t=2, the velocity of the particle is 4+2×2=8 m/s.
After t seconds, the velocity of the particle is 4+2t m/s.
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