Question

An object starts from rest and moves under the acceleration a = 4i its position after 3 s is given by 7i+4j what is its initial position

Answer 1

Here acceleration ‘a’ seems to be constant that is u = 0.

From equation of motion S = ut + ½ at ^2.  Let us consider s = x; x = 0 x 3 + ½ x 4i x 3 x 3 + X0.  

Then, x = X0 + 8i; y = Y0; X0 + 18i= 7i; X0 = - 11j; Yo = 4 j. Thus, the initial position will become – 11i + 4j.

Answer 2

Step-by-step explanation:

Here acceleration ‘a’ seems to be constant that is u = 0.

From equation of motion S = ut + ½ at ^2.  Let us consider s = x; x = 0 x 3 + ½ x 4i x 3 x 3 + X0.  

Then, x = X0 + 8i; y = Y0; X0 + 18i= 7i; X0 = - 11j; Yo = 4 j. Thus, the initial position will become – 11i + 4j.