Question

An object starts from rest and moves with constant acceleration of 2m/s2 along x axis . During journey from x=4m to x = 16m,it's average velocity is?

Answer 1

I don't know it's ans

Answer 2

Hey dear,

● Answer -
v = 6 m/s

● Explaination -
# Given -
u = 0
a = 2 m/s^2
x1 = 4 m
x2 = 16 m

# Solution -
For x1 = 4 m,
v1^2 = u^2 + 2as
v1^2 = 0 + 2×2×4
v1^2 = 16
v1 = 4 m/s

For x2 = 16 m,
v2^2 = u^2 + 2as
v2^2 = 0 + 2×2×16
v2^2 = 64
v2 = 8 m/s

Average velocity from x=4 to x=16 is -
v = (v1 + v2) / 2
v = (4 + 8) / 2
v = 6 m/s

Therefore, average velocity of object is 6 m/s.

Hope this helps you...