Question

An object starts from rest attained a velocity of 42 km/h
in 5 seconds at uniform rate. The acceleration of object is 4/3ms2 7/3m/s2 7/4m/s 2 5/3m/s 2​

Answer 1

if object has constant acceleration then

dv/dt = a (a is constant)

dv=adt

42-0 = a× 5

a= 8.4m/s²

Answer 2

Answer:

3. 7/3 m/$s^{2}$

Explanation:

Given:

Final velocity: v = 42km/h = $\frac{42 * 1000}{3600}$ = 11.67m/s

Time : t = 5 s

Initial velocity: u = 0

Acceleration: a = ?

v = u + at

a= $\frac{v-u}{t}$

a=$\frac{11.67-0}{5}$

a=2.33m/$s^{2}$ = 7/3m/$s^{2}$