Question

An object starts from rest attaining the speed of 50m/s after travelling a distance of 400m. Find the acceleration of the object​

Answer 1

Answer:

Given :-

• An object starts from rest attaining the speed of 50 m/s after travelling a distance of 400 m.

To Find :-

• What is the acceleration of the object.

Formula Used :-

$\clubsuit$ Third Equation Of Motion Formula :

$\mapsto \sf\boxed{\bold{\pink{v^2 =\: u^2 + 2as}}}$

where,

• v = Final Velocity
• u = Initial Velocity
• a = Acceleration
• s = Distance Covered

Solution :-

Given :

• Final Velocity (v) = 50 m/s
• Initial Velocity (u) = 0 m/s
• Distance Covered (s) = 400 m

According to the question by using the formula we get,

$\longrightarrow \sf (50)^2 =\: (0)^2 + 2as$

$\longrightarrow \sf 50 \times 50 =\: 0 \times 0 + 2a(400)$

$\longrightarrow \sf 2500 =\: 0 + 2 \times a \times 400$

$\longrightarrow \sf 2500 =\: 0 + 800a$

$\longrightarrow \sf 2500 - 0 =\: 800a$

$\longrightarrow \sf 2500 =\: 800a$

$\longrightarrow \sf \dfrac{25\cancel{00}}{8\cancel{00}} =\: a$

$\longrightarrow \sf \dfrac{25}{8} =\: a$

$\longrightarrow \sf 3.125 =\: a$

$\longrightarrow \sf\bold{\red{a =\: 3.125\: m/s^2}}$

${\small{\bold{\underline{\therefore\: The\: acceleration\: of\: the\: object\: is\: 3.125\: m/s^2\: .}}}}$