Question

an object starts from rest attains a velocity of 42 per hour in 5 second at uniform with the acceleration of object is​

Answer 1

• initial velocity=u=0m/s
• Final velocity=42km/h=v
• Time=t=5s

Convert v into m/s

$\\ \sf\longmapsto v=42\times \dfrac{5}{18}=11.6m/s$

We know

$\boxed{\sf Acceleration=\dfrac{v-u}{t}}$

$\\ \sf\longmapsto Acceleration=\dfrac{11.6-0}{5}$

$\\ \sf\longmapsto Acceleration=\dfrac{11.6}{5}$

$\\ \sf\longmapsto Acceleration=2.3m/s^2$