An object starts from rest recover a distance of 125m with acceleration of 10m/s find its final velocity and velocity 5 sec after starting journey
Answers
Answer:
Explanation:
• In the given question information given about an object which is in rest and start acceleration of 10 m/s^2 and covers a certain distance.
• We have to find the final velocity and velocity after 4 sec.
• According to given question :
Solution:
Given:
➜ An object starts from rest recover a distance of 125m with acceleration of 10m/s.
Find:
➜ Find its final velocity and velocity 5 sec after starting journey.
According to the given question:
➜ 0 = initial velocity.
➜ 125 m = distance.
➜ 10 m/s² = acceleration.
Know terms:
➜ Initial velocity = (u)
➜ Final velocity = (v)
➜ Acceleation = (a)
➜ Time = (t)
By using second equation of motion :
➜ v² = u² + 2as
➜ v² = 0² + 2 × 10 × 125
➜ v² = 2500
➜ v = √2500
➜ v = 50 m/s
By using second equation of motion:
➜ v = u + at
➜ v2 = 0 + 10 × 5
➜ v2 = 50 m/s
Therefore, v2 = 50 m/s is the required answer.