Physics, asked by Kanare7036, 11 months ago

An object starts from rest recover a distance of 125m with acceleration of 10m/s find its final velocity and velocity 5 sec after starting journey

Answers

Answered by BrainlyConqueror0901
24

Answer:

{\bold{\therefore Final\:velocity=50\:m/s}}

{\bold{\therefore Velocity\:after\:5\:sec=50\:m/s}}

Explanation:

{\bold{\huge{\underline{SOLUTION-}}}}

• In the given question information given about an object which is in rest and start acceleration of 10 m/s^2 and covers a certain distance.

• We have to find the final velocity and velocity after 4 sec.

 \underline \bold{Given : } \\\\ \implies Initial \: velocity (u) = 0\\ \\ \implies Distance(s) = 125 \: m \\ \\ \implies Acceleration(a) = 10 \: m/ {s}^{2}  \\  \\   \underline \bold{To \: Find :} \\ \\ \implies Final \: velocity( v_{ 1 } ) = ? \\\\  \implies Velocity \: after \: 5 \: sec(  v_{2} ) = ?

• According to given question :

 \bold{By \: Second \: equation \: of \: motion : } \\\\  \implies  {v}^{2}  =  {u}^{2}  + 2as \\  \\\implies  {v}^{2}  =  {0}^{2}  + 2 \times 10 \times 125 \\ \\ \implies  {v}^{2}  = 2500 \\\\  \implies v =  \sqrt{2500}  \\  \\ \bold{\implies v = 50 \: m/s} \\  \\  \bold{for \: velocity \: afte r \: 5 \: sec : } \\   \\  \bold{By \: First \: equation \: of \: motion : } \\  \\\implies  v  = u + at \\ \\ \implies v_{ 2 } = 0 + 10 \times 5\\ \\  \bold{\implies v_{ 2 } = 50 \: m/s}

Answered by Anonymous
22

Solution:

Given:

➜ An object starts from rest recover a distance of 125m with acceleration of 10m/s.

Find:

➜ Find its final velocity and velocity 5 sec after starting journey.

According to the given question:

➜ 0 = initial velocity.

➜ 125 m = distance.

➜ 10 m/s² = acceleration.

Know terms:

➜ Initial velocity = (u)

➜ Final velocity = (v)

➜ Acceleation = (a)

➜ Time = (t)

By using second equation of motion :

➜ v² = u² + 2as

➜ v² = 0² + 2 × 10 × 125

➜ v² = 2500

➜ v = √2500

➜ v = 50 m/s

By using second equation of motion:

➜ v = u + at

➜ v2 = 0 + 10 × 5

➜ v2 = 50 m/s

Therefore, v2 = 50 m/s is the required answer.

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