Question

an object starts from rest travels with anaccelaration of 5m/s what will be the velocity after 3s ?

Answer 1

Answer:

$final \: velocity(v) = 15m.se {c}^{ - 1}$

Explanation:

$accelaration(a) = 5m.se {c}^{2} \\ initial \: velocity(u) = 0 \: m.se {c}^{ - 1} \\ time(t) = 3sec \\ final \: velocity(v) = \: ? \\ = )a = \frac{v - u}{t} \\ = ) \frac{v - 0}{3} = 5 \\ = )v - 0 = 15 \\ = )v = 15$

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Answer 2

$\huge \mathbb{\boxed{\red{Question\:}}}</p><p>$

An object starts from rest travels with an accelaration of 5m/s what will be the velocity after 3s ?

$\huge \mathbb{\boxed{\red{Solution\:}}}$

Given that the object starts from rest and it acceleration of 5m/s². What is the final velocity of the object after 3 seconds.

u = 0 ; a = 5m/s² ; t = 3sec ; v = ?

We can find the final velocity by using first law of motion.

v = u + at

v = 0 + 5 × 3

v = 15m/s

Hence the final velocity of object is 15m/s.