Question

An object starts from rest with uniform acceleration and covers 100 m in 10 s. Find the speed of the object

just after covering 50 m.​

Answer 1

Explanation:

Given that an object starting from rest with uniform acceleration , covers 100m in 10s.

We have to find speed of object after covering 50m.

From the given data : Initial speed (u) = 0 m/s. Distance (s) = 100m. Time (t) = 10s.

At first to find acceleration we will use 2nd equation of motion i.e. s = ut + ½ at²

Substituting values,

→ 100 = 0 × 10 + ½ × a × 10²

→ 100 = 0 + ½ × a × 100

→ 100 = 50a

→ a = 100/50

→ a = 2 m/s²

Now we have acceleration i.e. a = 2 m/s². Now to find final velocity we can use 3rd equation of motion as distance has been given particularly i.e. v² - u² = 2as

Substituting values,

→ v² - 0² = 2 × 2 × 50

→ v² - 0 = 200

→ v² = 200

→ v = √200

→ v = 14.14 m/s

∴ Final speed of object = 14.14 m/s (Ans.)

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Answer 2

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$\sf{\purple{\bold{Answer: \: v = 10√2 \: m/s}}}$