Physics, asked by shreyasrivastava2005, 3 months ago

An object starts motion initial velocity 10 metre/ second under the effect of retardation 4 m/s2 . Then the distance travelled by object in 3 second is 12 metre.



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Answers

Answered by ExᴏᴛɪᴄExᴘʟᴏʀᴇƦ
57

Answer

  • The statement is false and the distance traveled will be 48 m

Explanation

Given

  • Initial velocity = 10 m/s
  • Retardation = 4 m/s²
  • Time = 3 sec

To Find

  • Distance Travelled

Formula Used

  • s = ut+½at² [Second Equation of Motion]

Solution

Distance Covered

→ s = ut+½at²

  • u = Initial Velocity = 10 m/s
  • t = Time = 3 sec
  • a = Acceleration (Here Retardation/Negative Acceleration) = 4 m/s²
  • s = Distance = ?

→ s = 10×3 + ½ × 4 × 3²

→ s = 30 + ½ × 4 × 9

→ s = 30 + 2×9

→ s = 30+18

→ s = 48 meter

Know More

Other equations of Motion!!

  • v = u+at
  • v²-u² = 2as

Anonymous: Superb anna !!
Cosmique: splendid !! :D
Answered by Anonymous
200

REQUIRED ANSWER :

The above statement is false.

The correct answer will be 48 m.

EXPLAINATION :

 \\

GIVEN :-

  • Initial velocity (u) = 10 m/s

  • Retardation (a) = 4 m/s²

  • Time (t) = 3 sec

TO FIND :-

  • Distance travelled (s)

SOLUTION :-

✰ By using :-

➥ \large  \underline{\boldsymbol \color{green}{Second~ equation ~ of ~ motion: -}}

\large\color{blue} { \boxed {\boxed{ \bf\color{blue}{ s\: =\: ut\: +\: ½\: at² }}}}

WHERE :

  • s = distance covered

  • u = initial velocity

  • t = time

  • a = retardation

━━━━━━━━━━━━━━━━━━━━━━━━━━

Putting all values :

➙ s = (10 × 3) + ½ × 4 × 3²

➙ s = 30 + ½ × 4 × 9

➙ s = 30 + ½ × 36

s = 30 + 18

➙ s = 48

━━━━━━━━━━━━━━━━━━━━━━━━━━

the distance covered by the object = 48 m.

●❯──────────────────────❮●

More information

First equation of motion :-

\large\color{grey} { \boxed {\underline{ \bf\color{grey}{v =u + at }}}}

Where :-

  • v = final velocity

  • u = initial velocity

  • a = acceleration

  • t = time taken

✦ Second equation of motion :-

\large\color{grey} { \boxed {\underline{ \bf\color{grey}{ s\: =\: ut\: +\: ½\: at² }}}}

Where :-

  • s = distance covered

  • u = initial velocity

  • t = time taken

✦ Third equation of motion :-

\large\color{grey} { \boxed {\underline{ \bf\color{grey}{ v²\: -\: u²\: =\: 2as}}}}

Where :-

  • v = final velocity

  • u = initial velocity

  • a = acceleration

  • s = distance covered

●❯──────────────────────❮●


Cosmique: Nicee!! :D
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