An object starts motion initial velocity 10 metre/ second under the effect of retardation 4 m/s2 . Then the distance travelled by object in 3 second is 12 metre.
true
false
Answers
Answered by
57
Answer
- The statement is false and the distance traveled will be 48 m
Explanation
Given
- Initial velocity = 10 m/s
- Retardation = 4 m/s²
- Time = 3 sec
To Find
- Distance Travelled
Formula Used
- s = ut+½at² [Second Equation of Motion]
Solution
✭ Distance Covered
→ s = ut+½at²
- u = Initial Velocity = 10 m/s
- t = Time = 3 sec
- a = Acceleration (Here Retardation/Negative Acceleration) = 4 m/s²
- s = Distance = ?
→ s = 10×3 + ½ × 4 × 3²
→ s = 30 + ½ × 4 × 9
→ s = 30 + 2×9
→ s = 30+18
→ s = 48 meter
Know More
Other equations of Motion!!
- v = u+at
- v²-u² = 2as
Anonymous:
Superb anna !!
Answered by
200
❏ REQUIRED ANSWER :
The above statement is false.
The correct answer will be 48 m.
❏ EXPLAINATION :
★ GIVEN :-
- Initial velocity (u) = 10 m/s
- Retardation (a) = 4 m/s²
- Time (t) = 3 sec
★ TO FIND :-
- Distance travelled (s)
★ SOLUTION :-
✰ By using :-
✯ WHERE :
- s = distance covered
- u = initial velocity
- t = time
- a = retardation
━━━━━━━━━━━━━━━━━━━━━━━━━━
♣ Putting all values :
➙ s = (10 × 3) + ½ × 4 × 3²
➙ s = 30 + ½ × 4 × 9
➙ s = 30 + ½ × 36
➙ s = 30 + 18
➙ s = 48 ★
━━━━━━━━━━━━━━━━━━━━━━━━━━
⛬ the distance covered by the object = 48 m.
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✪ More information ✪
✦ First equation of motion :-
Where :-
- v = final velocity
- u = initial velocity
- a = acceleration
- t = time taken
✦ Second equation of motion :-
Where :-
- s = distance covered
- u = initial velocity
- t = time taken
✦ Third equation of motion :-
Where :-
- v = final velocity
- u = initial velocity
- a = acceleration
- s = distance covered
●❯──────────────────────❮●
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