Question

an object starts moving from rest on a straight line path with uniform acceleration and covers a distance of 100m in first 10s .the distance it covers in next 5 s is

Answer 1

Distance covered in first 10 seconds is 100 m
So,
S = ut + 0.5at²
100 m = 0 + (0.5a (10 s)²)
a = 2 m/s²

Distance covered in first 15 seconds
S = ut + 0.5at²
= 0 + (0.5 × 2 m/s² × (15 s)²)
= 225 m

Distance covered in next 5 seconds = Distance covered in first 15 seconds - Distance covered in first 10 seconds
= 225 m - 100 m
= 125 m

Distance covered in next 5 seconds is 125 m