An object starts moving from rest on a straight line path with uniform acceleration and covers a distance of 100 m in first 10s. The distance it covers in next 5 s is
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distance = Speed × time
100 = Speed × 10
100/10 = Speed
10m/s = Speed
In the second case,
distance = Speed × time
distance = 10 × 5
distance = 50m
now the total distance it covers in
10+5 seconds = 15 seconds
is 100 +50=150
100 = Speed × 10
100/10 = Speed
10m/s = Speed
In the second case,
distance = Speed × time
distance = 10 × 5
distance = 50m
now the total distance it covers in
10+5 seconds = 15 seconds
is 100 +50=150
pratyushharsh6ovejvy:
An object starts moving from rest on a straight line path with uniform acceleration and covers a distance of 100 m in first 10s. The distance it covers in next 5 s is
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