Question

An object starts moving from rest on a straight line path with uniform acceleration and covers a distance from 100m in first 10s .The distance it covers in next 5s is?

Answer 1

The answer will be 50 metre
Explanation -
10 sec = 100, then
5 second = 50 metre

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Plz mark the answer as brainly answer................

Answer 2

Distance covered in first 10 seconds is 100 m

So,

S = ut + 0.5at²

100 m = 0 + (0.5a (10 s)²)

a = 2 m/s²

Distance covered in first 15 seconds

S = ut + 0.5at²

= 0 + (0.5 × 2 m/s² × (15 s)²)

= 225 m

Distance covered in next 5 seconds = Distance covered in first 15 seconds - Distance covered in first 10 seconds

= 225 m - 100 m

= 125 m

Distance covered in next 5 seconds is 125 m

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