An object starts moving from the rest with
uniform acceleration and travels 20 m in first
2 s. What will be its velocity after 10 s from the
start and displacement of the particle in 10th
second?
pls answer i'll mark as brainliest
Answers
Answer:
V = u + at
After 5s
25 = u + 5a ——(1)
After 8s
34 = u + 8a ——(2)
Subtract equation (1) from equation (2)
34 - 25 = u + 8a - u - 5a
9 = 3a
a = 3 m/s^2
Substitute a = 3m/s^2 in equation (1)
25 = u + 5*3
u = 10 m/s
Distance travelled in 10th second
S = u + a(n - 1/2)
S = 10 + 3*(12 - 1/2)
S = 44.5m
Distance travelled in 10th second is 44.5m
Explanation:
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Motion in a Straight Line
Problems on Equation of Motion
An object starting from res...
PHYSICS
An object starting from rest travels 20 m in first 2 s and 160 m in next 4 s. What will be the velocity after 7 s from the start?
December 20, 2019
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Bhavani Waswani
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ANSWER
Displacement in first 2 s, s
1
=20 m
Displacement in first 6 s, s
2
=20+160=180 m
Note that
s
1
=5×2
2
s
2
=5×6
2
It can be concluded that s=5 t
2
.......(i)
s∝t
2
⟹Acceleration is constant
From second equation of motion for uniformly accelerated motion,
s=ut+(1/2)at
2
..........(ii)
From (i) and (ii),
a/2=5
a=10 m/s
2
At the end of 7 s,
v=u+at
=0+10×7
=70 m/s
December 20, 2019