Question

an object starts moving in straight line from rest and after 2 seconds velocity becomes 20 metre per second then find the total distance travelled by the object
Guys plz answer fast its urgent ​

Answer 1

Answer: D= 20m

Explanation: V1 = zero  , T = 2 s , V2 = 20m/s

*d = V1 t + 1/2 a t²                                                      , a = v/t = 20/2 = 10 m/s²

d = 0×2 + 1/2 ×10×2²= 20m

Answer 2

Given :

• Initial velocity , u= 0 m/s
• Final velocity , v =20m/s
• Time , t= 2 sec

To Find :

The total distance travelled by the object

${\purple{\boxed{\large{\bold{Formula's}}}}}$

Kinematic equations for uniformly accelerated motion .

$\bf\:v=u+at$

$\bf\:S=ut+\frac{1}{2}at{}^{2}$

$\bf\:v{}^{2}=u{}^{2}+2aS$

and $\bf\:s_{nth}=u+\frac{a}{2}(2n-1)$

${\underline{\sf{Answer}}}$

We have to Find the distance travelled by the object

By First Equation of Motion

$\rm\:v=u+at$

Put the given values

$\sf\implies\:20=0+a\times2$

$\sf\implies\:a=\dfrac{20}{2}=10ms^{-2}....(1)$

Then ,

By using second Equation of motion

$\rm\:S=ut+\dfrac{1}{2}at{}^{2}$

Put the given values , then

$\sf\implies\:S=0\times2+\dfrac{1}{2}\times10\times4$

$\sf\implies\:S=0+\dfrac{4}{2}\times10$

$\sf\implies\:S=0+2\times10$

$\sf\implies\:S=20m$

Therefore, The total distance travelled by the object is 20 m.