Question

An object starts with initial velocity u at point A,then it,reached point B with velocity v ,and cover distance S in time t with uniform acceleration a,derive equation of motion (s=ut+1/2at^2) by using graph
.please answer.​

Answer 1

Answer:

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Step-by-step explanation:

Y=album(sec(x)/a)Putting a =1Y=ln(sec(x))Slope of this curve,Tan(θ)=dy/dx=tan(x) ;equation(1)θ=xAngular velocity of tangent i.e. ω=dθ/dt=dx/dt=2Hence dx/dt=2By equation (1) dy/dt =tan(x) dx/dtHence velocity along y direction is 2 tan(x)So acceleration along y,= 2 sec(x) sec(x)At x=π/4, acceleration=2 √2 √2 =4