Question

An object starts with velocity 5 m/s and after time 10s it has the velocity of 9m/s. Then the displacement is...​

Answer 1

Answer:

• 70 metres is the required displacement

Explanation:

According to the Question

It is given that,

• Initial velocity, u = 5m/s
• Final velocity ,v = 9m/s
• Time taken ,t = 10s

we have to calculate the displacement of the object .

Firstly we calculate the acceleration of the object .

As we know that acceleration is defined as the rate of change in velocity at per unit time.

• a = v-u/t

by substituting the value we get

⇢ a = 9-5/10

⇢ a = 4/10

⇢ a = 0.4m/s²

Now, calculating the displacement of the object

Using Kinematics Equation

• v² - u² = 2as

where

s denote displacement

⇢ 9² - 5² = 2 × 0.4 × s

⇢ 81 - 25 = 0.8 × s

⇢ 56 = 0.8 × s

⇢ s = 56/0.8

⇢ s = 70 m

• Hence, the displacement of the object is 70 meters.

Answer 2

Answer:

Given :-

• An object starts with velocity of 5 m/s and after time 10 seconds it has the velocity of 9 m/s.

To Find :-

• What is the displacement.

Solution :-

First, we have to find the acceleration :

As we know that :

$\clubsuit$ First Equation Of Motion Formula :

$\bigstar \: \: \sf\boxed{\bold{\pink{v =\: u + at}}}\: \: \: \bigstar$

where,

• v = Final Velocity
• u = Initial Velocity
• a = Acceleration
• t = Time Taken

Given :

• Initial Velocity = 5 m/s
• Final Velocity = 9 m/s
• Time Taken = 10 seconds

According to the question by using the formula we get,

$\implies \bf v =\: u + at$

$\implies \sf 9 =\: 5 + a(10)$

$\implies \sf 9 =\: 5 + 10a$

$\implies \sf 9 - 5 =\: 10a$

$\implies \sf 4 =\: 10a$

$\implies \sf \dfrac{4}{10} =\: a$

$\implies \sf 0.4 =\: a$

$\implies \sf\bold{\purple{a =\: 0.4\: m/s^2}}$

Hence, the acceleration of an object is 0.4 m/s² .

Now, we have to find the displacement of an object :

As we know that :

$\clubsuit$ Second Equation Of Motion Formula :

$\bigstar \: \: \sf\boxed{\bold{\pink{s =\: ut + \dfrac{1}{2} at^2}}}\: \: \: \bigstar$

where,

• s = Distance Covered or Displacement
• u = Initial Velocity
• t = Time Taken
• a = Acceleration

Given :

• Initial Velocity = 5 m/s
• Time Taken = 10 seconds
• Acceleration = 0.4 m/s²

According to the question by using the formula we get,

$\implies \bf s =\: ut + \dfrac{1}{2} at^2$

$\implies \sf s =\: (5)(10) + \dfrac{1}{2} \times (0.4)(10)^2$

$\implies \sf s =\: (5 \times 10) + \dfrac{1}{2} \times (0.4)(10 \times 10)$

$\implies \sf s =\: 50 + \dfrac{1}{2} \times 0.4 \times 100$

$\implies \sf s =\: 50 + \dfrac{1}{\cancel{2}} \times {\cancel{40}}$

$\implies \sf s =\: 50 + 20$

$\implies \sf\bold{\red{s =\: 70\: m}}$

$\therefore$ The displacement of an object is 70 m.