Question

An object strating from rest travel with unifrom acceleration of 5m/s2. what will be its velocity after 3s

Answer 1

Explanation:

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Answer 2

Answer :-

15m/s

Explanation :-

Given :

Acceleration = 5m/s^2

Time = 3s

Initial velocity = 0 (as it started from rest)

To Find :

Final velocity = ?

Solution :

According to the first equation of motion,

$\boxed{\sf{}v=u+at}$

where

v is the final velocity,

u is the initial velocity,

a is the acceleration and,

t is the time taken.

Put their values and find “v”

$\implies \sf{}v=0+5m/s^2\times 3s$

$\sf{}\implies 5m/s^2\times 3s$

$\mapsto \sf{}15m/s$

Therefore,final velocity is equal to 15m/s

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Equations of Motion:

Relation among velocity, distance, time and acceleration is called equation of motion.

There are three equations of motion:

$\sf{}First\ equation\ of\ motion: \ v = u + at$

$\sf{}Second\ equation\ of\ motion: \ s = ut + \dfrac{1}{2}at^2$

$\sf{}Third\ equation\ of\ motion: \ v^2-u^2= 2as$